Reported September 2024
IBMhash table

Count Similar Pairs

Reported by candidates from IBM's online assessment. Pattern, common pitfall, and the honest play if you blank under the timer.

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IBM's September OA included Count Similar Pairs, a problem that trips up candidates who overthink symmetry. You're given a dataset and need to count pairs that meet a similarity criterion. The trick is recognizing that you're not looking for deep algorithmic complexity but rather the right data structure to avoid a timeout. StealthCoder can feed you the exact pattern in seconds if you blank on the indexing logic during the live assessment.

Pattern and pitfall

Count Similar Pairs usually asks you to find pairs of elements (often indices or values) that satisfy a similarity condition, typically within some threshold or matching a specific property. The naive approach loops through every pair, which works for small inputs but fails at scale. The real solve uses a hash table or sorted array to group similar candidates, then counts valid pairs in a single pass. The gotcha: candidates often misread the pairing rule (ordered vs. unordered, inclusive vs. exclusive thresholds) and end up double-counting or missing edges. During the live OA, if the logic fuzzes, StealthCoder clarifies the exact grouping strategy without you having to re-read the problem.

If you see this problem in your OA tomorrow, the play is to recognize the pattern in 30 seconds. StealthCoder buys you that recognition.

If this hits your live OA

You can drill Count Similar Pairs cold, or you can hedge it. StealthCoder runs invisibly during screen share and surfaces a working solution in under 2 seconds. The proctor sees the IDE. They don't see what's behind it. Built by an Amazon engineer who passed his OA cold and still thinks the filter is broken.

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Related leaked OAs

⏵ The honest play

You've seen the question. Make sure you actually pass IBM's OA.

IBM reuses patterns across OAs. Built by an Amazon engineer who passed his OA cold and still thinks the filter is broken. Works on HackerRank, CodeSignal, CoderPad, and Karat.

Count Similar Pairs FAQ

Is this a hash-table or sorting problem?+

Both can work. Hash tables are faster if you group by property and count pairs within each group. Sorting works if you need to find pairs within a distance threshold. IBM's version likely expects hash-table logic for O(n) efficiency. Pick based on the exact similarity rule given in your prompt.

Do I count (i, j) and (j, i) as the same pair or different?+

Always clarify from the problem statement. Most counting problems want unordered pairs, so (i, j) and (j, i) are the same. If the problem says 'count all pairs', re-read the examples. A single example will resolve this in seconds.

What's the typical time complexity IBM expects?+

O(n) or O(n log n). O(n^2) brute force fails on medium inputs. Hash tables give O(n) if grouping is deterministic. Sorting plus iteration is O(n log n). Aim for hash-table first unless the similarity rule requires ordering.

How do I avoid off-by-one errors on thresholds?+

Work through the provided examples by hand. Check boundary cases: are equal elements similar? Does similarity include the threshold or exclude it? IBM's OAs often include an example where threshold=0 or elements are identical. Use that to lock in the comparison operator.

Is there a pattern to IBM's pair-counting problems?+

IBM tends to ask for O(n) solutions using hash maps or modular arithmetic. Count Similar Pairs in September likely hinges on recognizing which elements group together, then counting combinations within groups. If you see 'similar', think 'group first, count second'.

Problem reported by candidates from a real Online Assessment. Sourced from a publicly-available candidate-aggregated repository. Not affiliated with IBM.

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