MEDIUMasked at 1 company

Minimum Array Changes to Make Differences Equal

A medium-tier problem at 23% community acceptance, tagged with Array, Hash Table, Prefix Sum. Reported in interviews at Airbus SE and 0 others.

Founder's read

You've got an array and need to make all element differences equal with minimum changes. This problem looks simple at first glance, then punches you in the mouth. The 23% acceptance rate isn't a fluke. Airbus has asked it, which means it's not a gimme in their screening rounds. Most candidates either brute force straight into TLE or miss the constraint entirely and waste time on a wrong approach. If this one shows up on your OA and you blank, StealthCoder runs invisible during screen share and surfaces a working solution in seconds so you move on to the next problem instead of burning 40 minutes.

Companies asking
1
Difficulty
MEDIUM
Acceptance
23%

Companies that ask "Minimum Array Changes to Make Differences Equal"

If this hits your live OA

Minimum Array Changes to Make Differences Equal is the kind of problem that decides whether you pass. StealthCoder reads the problem on screen and surfaces a working solution in under 2 seconds. Invisible to screen share. The proctor sees nothing. Built by an Amazon engineer who used it to pass JPMorgan's OA and system design loop.

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What this means

The trick is recognizing that you can't just pick any arbitrary target difference. You need to figure out what difference values are even worth considering, then count the cost of each. Hash Table lets you aggregate the current differences in your array and Prefix Sum or careful iteration lets you compute the cost of making all differences equal to a candidate value. The pitfall is thinking you have to check every possible difference value (that's exponential in array size). Smart candidates constrain the search space by observing that only differences that already exist in the array, or differences near the median of existing differences, are worth evaluating. Array manipulation is straightforward once you've identified the target, but getting there requires the pattern. StealthCoder is the safety net for the one candidate who didn't see the constraint reduction pattern during live assessment.

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The honest play

You know the problem. Make sure you actually pass it.

Minimum Array Changes to Make Differences Equal recycles across companies for a reason. It's medium-tier, and most candidates blank under the timer. StealthCoder is the hedge: an AI overlay invisible during screen share. It reads the problem and surfaces a working solution in under 2 seconds. Built by an Amazon engineer who used it to pass JPMorgan's OA and system design loop. Works on HackerRank, CodeSignal, CoderPad, and Karat.

Minimum Array Changes to Make Differences Equal interview FAQ

How hard is this really compared to other medium arrays?+

The 23% acceptance rate tells you it's harder than typical medium. Most medium arrays sit around 40-50%. This one requires you to see a non-obvious constraint reduction before brute force becomes feasible. The algorithmic work itself is straightforward, but the insight isn't.

Is this still asked at major tech companies?+

It's reported by Airbus in our data. Companies at that scale use problems like this to filter out candidates who jump to code without thinking constraints through first. Not hyperfrequent, but it appears in screening rounds for companies that value systems thinking.

Do I need Hash Table and Prefix Sum together?+

Hash Table is core for grouping differences and counting frequency. Prefix Sum helps optimize the cost calculation phase. You might not need both simultaneously, but understanding how they work together in this context is what separates AC from TLE submissions.

What's the trick most people miss?+

Assuming you have to iterate over all possible difference values. You don't. The differences you already have in your array, plus differences around them, are usually sufficient candidates to check. That constraint reduction is the whole problem.

How do I avoid timeout on this?+

Identify which difference values are worth evaluating (usually O(n) candidates, not exponential). Use Hash Table to count existing difference frequencies in O(n). Then for each candidate, compute the cost in O(n) or better. Total complexity should be O(n squared) or better, not exponential brute force.

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