Minimum Length of Anagram Concatenation
A medium-tier problem at 40% community acceptance, tagged with Hash Table, String, Counting. Reported in interviews at UKG and 1 others.
You've got a string and need to find the shortest result after concatenating anagrams. This problem hits the sweet spot where the obvious greedy approach fails and you need to think about what 'anagram' really means in terms of character frequency. It's been asked at UKG and Turing, and with a 39.7% acceptance rate, most candidates either miss the core insight or overcomplicate the logic. If you blank on this during your live assessment, StealthCoder surfaces a working solution in seconds, invisible to the proctor.
Companies that ask "Minimum Length of Anagram Concatenation"
Minimum Length of Anagram Concatenation is the kind of problem that decides whether you pass. StealthCoder reads the problem on screen and surfaces a working solution in under 2 seconds. Invisible to screen share. The proctor sees nothing. Built by an engineer who got tired of watching his cohort grind for six months and still get filtered at the OA stage.
Get StealthCoderThe trick is recognizing that you're not concatenating words to form new anagrams. You're removing characters from the original string by identifying which characters appear in all remaining anagrams of it. The pattern: find the minimum frequency of any character in the string, then remove that frequency from every character. If a character appears 5 times and another appears 2 times, you can only 'match' 2 of them. Hash tables or a simple frequency count solves this, but the jump from 'concatenate anagrams' to 'minimum frequency math' is where candidates usually derail. It's a counting problem dressed in anagram language. StealthCoder is your hedge for the one detail you didn't drill in prep.
Pattern tags
You know the problem.
Make sure you actually pass it.
Minimum Length of Anagram Concatenation recycles across companies for a reason. It's medium-tier, and most candidates blank under the timer. StealthCoder is the hedge: an AI overlay invisible during screen share. It reads the problem and surfaces a working solution in under 2 seconds. Built by an engineer who got tired of watching his cohort grind for six months and still get filtered at the OA stage. Works on HackerRank, CodeSignal, CoderPad, and Karat.
Minimum Length of Anagram Concatenation interview FAQ
Is this problem actually about building anagrams from scratch?+
No. You're removing characters from the string based on the minimum frequency. Think of it as 'how many complete sets of matching characters can I remove,' not 'how many words can I rearrange.' The anagram constraint is the constraint, not the construction goal.
Why do most people get this wrong on first attempt?+
The problem statement suggests concatenation and rearrangement, so candidates try greedy matching or backtracking. The actual solution is arithmetic on character frequencies. Once you see the minimum-frequency pattern, the code is trivial. The hard part is recognizing what the problem is really asking.
How does this relate to the Hash Table and Counting topics?+
Hash Table or a frequency array counts how many times each character appears. Counting then identifies the minimum frequency across all characters. Those two steps are the entire solution. No complex data structures needed.
Is this problem still asked at FAANG-style companies?+
It's been reported at UKG and Turing so far. It's a medium-difficulty problem, so it fits the tier of screening rounds. It's not a classic problem yet, so less prep material exists. That makes it a good candidate for the one surprise that hits your OA.
What's the time complexity and why does it matter here?+
O(n) where n is the string length, because you scan once to count frequencies and once to compute the result. Space is O(1) or O(26) for lowercase English letters. Simple and efficient, so the blocker is the insight, not the execution.
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