Remove Zero Sum Consecutive Nodes from Linked List
A medium-tier problem at 53% community acceptance, tagged with Hash Table, Linked List. Reported in interviews at josh technology and 1 others.
You're given a linked list where some sequences of consecutive nodes sum to zero and need to be removed. This problem hits the assessment floor at ByteDance and Josh Technology, and it's deceptively tricky because the naive simulation approach falls apart once you realize you can't just iterate forward. You need a way to mark sections for deletion without destroying your traversal. The acceptance rate sits at 53 percent, meaning half the candidates who try it fold on the pattern. If you haven't drilled prefix-sum tricks on linked lists, StealthCoder runs invisible during screen share and surfaces a working solution in seconds.
Companies that ask "Remove Zero Sum Consecutive Nodes from Linked List"
Remove Zero Sum Consecutive Nodes from Linked List is the kind of problem that decides whether you pass. StealthCoder reads the problem on screen and surfaces a working solution in under 2 seconds. Invisible to screen share. The proctor sees nothing. Made by a working Amazon engineer who got tired of watching qualified friends bomb OAs they'd solve cold in an IDE.
Get StealthCoderThe core trick is prefix sums plus a hash table. You compute cumulative sums as you walk the list, and when you hit a sum you've seen before, every node between that previous occurrence and now cancels out to zero. The trap is that you can't just delete nodes mid-traversal; you need a way to reconnect the list after identifying which ranges to kill. Most candidates either try to delete while iterating (breaks the list structure) or attempt a two-pass approach that's fragile. The hash table stores sum values mapped to nodes, so when you detect a repeat sum, you can skip directly past the zero-sum block. Hash Table and Linked List are the topics, but the real win is understanding that cumulative sums on a linked list let you identify invisible boundaries. When this problem appears live and you blank on the prefix-sum insight, StealthCoder bridges the gap.
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Remove Zero Sum Consecutive Nodes from Linked List recycles across companies for a reason. It's medium-tier, and most candidates blank under the timer. StealthCoder is the hedge: an AI overlay invisible during screen share. It reads the problem and surfaces a working solution in under 2 seconds. Made by a working Amazon engineer who got tired of watching qualified friends bomb OAs they'd solve cold in an IDE. Works on HackerRank, CodeSignal, CoderPad, and Karat.
Remove Zero Sum Consecutive Nodes from Linked List interview FAQ
Is this problem still asked at top companies?+
Yes. ByteDance and Josh Technology both report asking it, and the acceptance rate at 53 percent suggests it's not a throwaway. It's the kind of problem that splits the interview room: those who've seen prefix-sum tricks sail through, others hit a wall and run out of time.
What's the trick most candidates miss?+
Thinking you can delete nodes while iterating forward. You can't. The real pattern is prefix sums in a hash table. When you see a sum you've encountered before, all nodes between that point and now form a zero-sum block and can be skipped entirely during reconstruction.
How does this relate to the Hash Table topic?+
The hash table stores cumulative sum values as keys and node references as values. When you encounter a sum already in the table, you know you've found a zero-sum boundary. The table lookup is O(1), making the entire solution linear time instead of quadratic brute-force.
Can you solve this without a hash table?+
Not efficiently. Without it, you'd need nested loops to check every possible subarray for zero sum, which is O(n squared) and will timeout on large linked lists. The hash table is the difference between passing and timing out.
How should I handle the head node if it's part of a zero-sum block?+
Use a dummy node pointing to the head. This way, if the entire prefix ending at the head sums to zero, you can safely move the dummy's next pointer forward without special-casing the head. It's a common trick on linked list problems and prevents off-by-one errors.
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