Create Components With Same Value
A hard-tier problem at 52% community acceptance, tagged with Array, Math, Tree. Reported in interviews at Sprinklr and 0 others.
Create Components With Same Value is a hard problem that combines tree decomposition with mathematical constraints. You're looking at a tree where you need to partition edges such that every resulting subtree has the same sum. Sprinklr has asked this. The acceptance rate is just over 50%, meaning half the candidates who attempt it don't get it right under time pressure. The trick isn't obvious from the problem statement alone. Most candidates waste time trying greedy approaches or brute-force enumeration before realizing the mathematical constraint that must hold. If this problem hits your live assessment and you blank on the pattern, StealthCoder surfaces a working solution invisibly while you're screen-sharing.
Companies that ask "Create Components With Same Value"
Create Components With Same Value is the kind of problem that decides whether you pass. StealthCoder reads the problem on screen and surfaces a working solution in under 2 seconds. Invisible to screen share. The proctor sees nothing. Made for the engineer who has done the work but might still blank with a webcam pointed at him.
Get StealthCoderThe core insight is mathematical before it's algorithmic. If you can partition the tree into k components, each with the same sum, then that sum value must divide the total tree sum evenly. But not every divisor works. You need to actually check which divisors allow a valid partition using depth-first search. The trap is assuming any divisor is viable or trying to construct partitions without validating they're achievable. The real work is a post-order DFS that tracks subtree sums and counts valid splits. Most candidates get stuck on the enumeration logic or the DFS bookkeeping. The topics array points to why this is hard: Array and Math upfront, but Tree, DFS, and Enumeration are where the solution lives. StealthCoder is your hedge if the DP or counting logic gets tangled mid-assessment.
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Create Components With Same Value recycles across companies for a reason. It's hard-tier, and most candidates blank under the timer. StealthCoder is the hedge: an AI overlay invisible during screen share. It reads the problem and surfaces a working solution in under 2 seconds. Made for the engineer who has done the work but might still blank with a webcam pointed at him. Works on HackerRank, CodeSignal, CoderPad, and Karat.
Create Components With Same Value interview FAQ
Is this really a hard problem?+
The acceptance rate is 52%, which means it sits in hard territory. Most candidates underestimate the mathematical setup or get lost in the DFS backtracking. It's not a simple tree traversal. You need both number theory insight and correct enumeration logic.
What's the most common mistake?+
Assuming any divisor of the total sum works as a component value. Candidates often skip the actual validation step. You must DFS and check whether a partition into that component value is actually possible.
How does enumeration fit the solution?+
You enumerate candidate divisors of the total sum, then for each divisor, you enumerate a DFS to verify whether a valid partition exists. It's enumeration layered on top of DFS, not just a single pass.
Why does this problem combine Math and Tree topics?+
The Math part filters candidate sums. The Tree and DFS parts verify feasibility. You can't skip the math. Without it, you'd DFS n times for n divisors. Math narrows the search space first.
Is this problem still asked?+
Sprinklr has reported it. The 50% acceptance rate suggests it's still in active circulation. It's the kind of hard problem that appears in second-round or senior-level assessments, not everyday OAs.
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