Find the Smallest Divisor Given a Threshold
A medium-tier problem at 64% community acceptance, tagged with Array, Binary Search. Reported in interviews at Expedia and 7 others.
You get an array of integers and a threshold. Find the smallest divisor such that when you divide each number by it (rounding up), the sum stays under the threshold. Expedia, PayPal, Oracle, and a handful of other companies have asked this. The trap: you don't iterate through divisors. You binary search for the answer. Most candidates see the numbers and think linear scan. That's slow enough to fail. If this problem hits your live assessment and you blank on the binary search angle, StealthCoder solves it in seconds, invisible to the proctor.
Companies that ask "Find the Smallest Divisor Given a Threshold"
Find the Smallest Divisor Given a Threshold is the kind of problem that decides whether you pass. StealthCoder reads the problem on screen and surfaces a working solution in under 2 seconds. Invisible to screen share. The proctor sees nothing. Built by an engineer who got tired of watching his cohort grind for six months and still get filtered at the OA stage.
Get StealthCoderThe trick is recognizing the search space. Divisors range from 1 to the max element in the array. As divisor increases, the sum of divided elements decreases monotonically. That monotonicity is your green light for binary search. You set low to 1, high to max(nums), then binary search for the smallest divisor where the sum of ceil divisions is at most the threshold. Many candidates get stuck on how to check a candidate divisor efficiently, or they miss that binary search applies at all. Binary Search and Array topics converge here. The acceptance rate around 64% suggests this problem punishes the linear-thinking approach and rewards pattern recognition. StealthCoder hedges the moment you realize you're about to code a brute-force divisor loop.
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Find the Smallest Divisor Given a Threshold recycles across companies for a reason. It's medium-tier, and most candidates blank under the timer. StealthCoder is the hedge: an AI overlay invisible during screen share. It reads the problem and surfaces a working solution in under 2 seconds. Built by an engineer who got tired of watching his cohort grind for six months and still get filtered at the OA stage. Works on HackerRank, CodeSignal, CoderPad, and Karat.
Find the Smallest Divisor Given a Threshold interview FAQ
Why can't I just loop through divisors from 1 upward?+
You can, but it times out. With max array values up to 10^6, a naive loop is O(max_element * n). Binary search cuts it to O(log(max_element) * n), which passes. The monotonic property of the problem makes binary search the intended path.
Is this actually asked at FAANG and big fintech?+
Reports show Expedia, PayPal, Oracle, IBM, and smaller firms like Millennium and ZScaler have asked it. It's not as common as Two Sum, but it appears regularly at companies that filter on algorithm fundamentals.
What's the main pitfall candidates hit?+
Not recognizing that divisor and result sum are monotonic. Candidates default to linear search or brute force. The second pitfall is implementing ceiling division wrong. Use (num + divisor - 1) // divisor or math.ceil(num / divisor) to avoid floating-point bugs.
How does this relate to the Array and Binary Search topics?+
You iterate the array to compute the sum of ceil divisions (Array work). You binary search the divisor range (Binary Search). Both skills chain together. If you're weak on either one, this problem exposes it immediately.
What's the acceptance rate telling me?+
Around 64% means roughly one third of submissions fail. Most failures are timeout or wrong answer on edge cases. It's a real filter, not a gimme. Expect to see this in OAs at mid-to-senior screening rounds.
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