Remove Letter To Equalize Frequency
A easy-tier problem at 18% community acceptance, tagged with Hash Table, String, Counting. Reported in interviews at tcs and 1 others.
Remove Letter To Equalize Frequency is a low-acceptance problem that TCS and Bloomberg have asked. On the surface it's about string manipulation and character counts, which makes candidates reach for the obvious brute-force solution. Most get stuck trying to optimize the wrong thing. The trick is knowing what state change matters after you remove one character, not overthinking the complexity. If this problem hits your live OA and the pattern doesn't click immediately, StealthCoder solves it in seconds, invisible to the proctor.
Companies that ask "Remove Letter To Equalize Frequency"
Remove Letter To Equalize Frequency is the kind of problem that decides whether you pass. StealthCoder reads the problem on screen and surfaces a working solution in under 2 seconds. Invisible to screen share. The proctor sees nothing. Built by an Amazon engineer who used it to pass JPMorgan's OA and system design loop.
Get StealthCoderThe problem asks you to remove exactly one letter and check if all remaining characters have equal frequency. The trap is iterating through every possible removal and recounting from scratch. The insight is understanding which frequency patterns are already valid or become valid after a single removal. You're looking for states where the max frequency differs from min by exactly one, or where max frequency minus one equals all others, or where only one character exists with a higher count. Once you count the frequencies upfront using a hash table, you can determine if removal is possible in a single pass. This is pattern recognition more than coding. If you haven't drilled this exact shape before, StealthCoder gives you the working solution the moment you hit it in assessment.
Pattern tags
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Remove Letter To Equalize Frequency recycles across companies for a reason. It's easy-tier, and most candidates blank under the timer. StealthCoder is the hedge: an AI overlay invisible during screen share. It reads the problem and surfaces a working solution in under 2 seconds. Built by an Amazon engineer who used it to pass JPMorgan's OA and system design loop. Works on HackerRank, CodeSignal, CoderPad, and Karat.
Remove Letter To Equalize Frequency interview FAQ
Why is acceptance rate so low for an Easy problem?+
The straightforward brute-force approach times out on most test cases, which fails a lot of submissions. The real solution requires recognizing the valid frequency patterns before removal, not after trying every deletion. Most candidates don't see the pattern without significant drilling.
Is this still asked at TCS and Bloomberg?+
Yes. Bloomberg and TCS both list it in recent hiring reports. It's not a high-volume problem, but it appears in their online assessments consistently enough that you need to know the trick before your OA.
What's the core algorithmic trick?+
Build a frequency table and a frequency-of-frequencies table. Then check if removal is possible by examining specific valid states: all chars have freq f except one has f+1, or all have freq f except one has freq 1, or only one unique character exists. This avoids the brute-force removal loop.
How does Hash Table fit into the solution?+
You use a hash table to count character frequencies in O(n) time, then another hash table to track how many characters have each frequency. This lets you validate the removal condition in constant time instead of re-scanning the string for every possible deletion.
Is this related to other frequency-balancing problems?+
Yes. It's similar to problems about making all elements equal by removing items or adjusting counts. The pattern recognition skill transfers: learn to think in terms of frequency distributions, not individual characters. That's the underlying topic across all three tags.
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