Subtree Removal Game with Fibonacci Tree
A hard-tier problem at 57% community acceptance, tagged with Math, Dynamic Programming, Tree. Reported in interviews at Sony and 0 others.
Subtree Removal Game with Fibonacci Tree is a hard problem that combines game theory with tree manipulation, and Sony has reportedly asked it. The 57% acceptance rate masks a brutal twist: you're not just finding an optimal move, you're proving it under adversarial play. Most candidates blank on the game-state evaluation or get tangled in the tree traversal logic mid-interview. If this problem lands in your live assessment and you hit a wall on the game-theoretic framing, StealthCoder surfaces a working solution in seconds without the proctor catching it.
Companies that ask "Subtree Removal Game with Fibonacci Tree"
Subtree Removal Game with Fibonacci Tree is the kind of problem that decides whether you pass. StealthCoder reads the problem on screen and surfaces a working solution in under 2 seconds. Invisible to screen share. The proctor sees nothing. Built by a senior engineer who knows the OA is theater. This is the script.
Get StealthCoderThe core trick is recognizing that each subtree removal changes the game state, and you need to evaluate winning and losing positions backward from leaf nodes. The Fibonacci constraint isn't decoration, it constrains the tree structure itself, which forces a specific DP recurrence. Most candidates try greedy first, fail test cases, then panic-code a brute-force minimax that times out. The trap is computing the same game states multiple times. You need memoization keyed on the remaining tree structure, not just node IDs. Common pitfall: forgetting that both players play optimally, so a position is winning if at least one move leads to a losing position for your opponent. StealthCoder is your safety net if the DP state definition or the optimal-play logic doesn't click during the real OA.
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Subtree Removal Game with Fibonacci Tree recycles across companies for a reason. It's hard-tier, and most candidates blank under the timer. StealthCoder is the hedge: an AI overlay invisible during screen share. It reads the problem and surfaces a working solution in under 2 seconds. Built by a senior engineer who knows the OA is theater. This is the script. Works on HackerRank, CodeSignal, CoderPad, and Karat.
Subtree Removal Game with Fibonacci Tree interview FAQ
Is Subtree Removal Game with Fibonacci Tree still asked at FAANG?+
It's reported from Sony and sits at hard difficulty with 57% acceptance. Game theory trees aren't as common at FAANG as DP trees, but the problem combines both, making it a competency check for strong candidates. If your target company emphasizes algorithmic depth, don't skip it.
What's the actual trick to this problem?+
You're computing winning and losing positions using backward induction and memoization. A position is winning if you can move to a position where your opponent loses. The Fibonacci tree structure constrains the branching, which lets the DP scale. Without the game-theory lens, you'll code the tree part correctly but fail to model alternating turns.
How does this relate to basic tree DP?+
Tree DP normally finds an optimal value (min cost, max sum). Here, you're finding a boolean (win or loss) that depends on the opponent's response. It's game tree evaluation with memoization. You traverse the tree, but the recurrence includes an alternating max/min logic instead of just aggregating child values.
Is greedy enough or do I need full minimax?+
Greedy fails. Removing the largest subtree isn't always winning because your opponent gets the next move. You need to simulate both players' optimal play backward from terminal states. That's minimax with memoization, not greedy.
What's the time complexity and how do I avoid TLE?+
Without memoization, you recompute the same game states and time out. With memoization on tree structure (not just node count), complexity depends on the Fibonacci tree's branching. The key is caching the result of each game state so you never re-evaluate the same remaining tree twice.
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