Middle of the Linked List
A easy-tier problem at 81% community acceptance, tagged with Linked List, Two Pointers. Reported in interviews at Bosch and 7 others.
You're coding for Bosch, Walmart Labs, or Goldman Sachs and they hand you a linked list. Find the middle node. Sounds trivial. Most candidates code the obvious solution: traverse the whole list, count nodes, traverse again to the midpoint. It works. It passes. But the real trick is the two-pointer approach, and if you blank on it during the assessment, StealthCoder surfaces the pattern in seconds, invisible to the proctor. This problem hits frequently enough across 8 major companies that it's worth knowing cold.
Companies that ask "Middle of the Linked List"
Middle of the Linked List is the kind of problem that decides whether you pass. StealthCoder reads the problem on screen and surfaces a working solution in under 2 seconds. Invisible to screen share. The proctor sees nothing. Made by an Amazon engineer who watched the leaked-problem repo become an industry secret. He decided you should have it too.
Get StealthCoderThe two-pointer technique is the key. You move one pointer one step at a time and another two steps. When the fast pointer reaches the end, the slow pointer is at the middle. No counting, no second pass, one clean loop. The trap is edge cases: odd-length lists, even-length lists, and which node you return when the list has two middle nodes. Most candidates either forget the fast pointer logic or return the wrong node under pressure. The one-pass solution is algorithmically superior, and it's exactly what interviewers at these companies expect to see. If the pattern doesn't click during your live OA, StealthCoder runs invisibly and hands you the working code so you can move on without panic.
Pattern tags
You know the problem.
Make sure you actually pass it.
Middle of the Linked List recycles across companies for a reason. It's easy-tier, and most candidates blank under the timer. StealthCoder is the hedge: an AI overlay invisible during screen share. It reads the problem and surfaces a working solution in under 2 seconds. Made by an Amazon engineer who watched the leaked-problem repo become an industry secret. He decided you should have it too. Works on HackerRank, CodeSignal, CoderPad, and Karat.
Middle of the Linked List interview FAQ
Is this really asked at Walmart Labs and Goldman Sachs?+
Yes. It appears in eight company interview reports, including tier-one firms like Goldman Sachs, Qualcomm, and Intuit. It's not a daily question, but it hits often enough that you should have a clean solution. The acceptance rate of 81% suggests most people who attempt it solve it, but that includes the inefficient two-pass approach.
What's the trick I'm missing?+
Two pointers at different speeds. Fast pointer moves two nodes per iteration, slow moves one. When fast hits the end, slow is at the middle. Most people default to counting then iterating, which wastes a pass and signals you don't know the pattern. This problem tests whether you know the two-pointer paradigm.
How does this relate to broader linked list interviews?+
Two-pointer technique is foundational for linked lists. It shows up in cycle detection, palindrome checking, and partition problems. If you get this one right, you signal mastery of a technique interviewers see again and again. It's a confidence signal more than a hard problem.
What if the list has an even number of nodes?+
Clarify with the interviewer which middle node they want. Most problems define it as the second middle node when length is even. Once you know the rule, adjust your loop condition accordingly. The two-pointer logic doesn't change, only the termination condition.
Why is the acceptance rate so high?+
It's tagged EASY for a reason. The brute force two-pass solution is straightforward. But the fact that 8 companies ask it suggests they care more about how cleanly you code the optimal approach than whether you solve it at all. High acceptance masks a bar on technique.
Want the actual problem statement? View "Middle of the Linked List" on LeetCode →